How do you solve the system of equations #8x - 2y = 48# and #3x - 4y = 1#?

1 Answer
Sep 28, 2016

#7 4/13 and y = 5 3/13#

Explanation:

One method of solving a system of equations is by eliminating one of the variables.

The best scenario is to have additive inverses.
The sum of additive inverses is 0. #-3x + 3x = 0#

#color(white)(xxxxxxxxx)8x -2y = 48# .....................A
#color(white)(xxxxxxxxx)3x -4y = 1# ........................B

Let's create additive inverses with the #y-#terms

#A xxcolor(red)(-2): -16xcolor(red)(+4y)=-96# ...............C
#color(white)(xxxxxx.x.x)3xcolor(red)( -4y) = 1# ........................B

Adding the equations will eliminate the y terms.

#C+B: color(white)(xxxx)-13x = -95#

#color(white)(xxxxxxxxxxxxx) x = 7 4/13#

Now find y,
Substitute #7 4/13# for #x# in B

#3 (95/13) -4y = 1#

#285/13 -1 = 4y#

#(285 -13)/(13 xx 4) = y#

#272/52 = y#

#5 3/13 = y#