# How do you solve the system of equations 9x - 3y = 3 and 3x + 8y = - 17?

Mar 10, 2017

$x = - \frac{1}{3}$

$y = - 2$

#### Explanation:

Here we have two equations.

$9 x - 3 y = 3 \to$ equation $1$

$3 x + 8 y = - 17 \to$ equation $2$

Multiply equation 2 by $3$, we get

$9 x + 24 y = - 51 \to$ equation $3$

Subtract the new equation $3$ from $1$

$9 x - 3 y = 3$

$- \left(9 x + 24 y = - 51\right)$

$0 x - 27 y = 54$

$\implies y = - 2$

Substitute in equation $2$

$3 x + 8 \left(- 2\right) = - 17$

$3 x - 16 = - 17$

$3 x = - 1$

$x = - \frac{1}{3}$