# How do you solve the system of equations k + t/2 = 7 and 2k + 3t = 26?

The solution is $\left(k , t\right) = \left(4 , 6\right)$

#### Explanation:

We have a system of equations

(1) $k + \frac{t}{2} = 7$

(2) $2 k + 3 t = 26$

Multiply (1) by 2 hence

$2 \cdot \left(k + \frac{t}{2}\right) = 14 \implies 2 k + t = 14$

and subtract from (2) hence

$\left(2 k + 3 t\right) - \left(2 k + t\right) = 26 - 14 \implies 2 t = 12 \implies t = 6$

hence $k + \frac{6}{2} = 7 \implies k = 7 - 3 = 4$