How do you solve the system of equations #x+5y-10=0# and #x=2y-8# using substitution?

1 Answer
Jun 16, 2016

#(x,y)=color(green)(""(-20/7,18/7))#
(see below for solution using substitution)

Explanation:

Given
[1]#color(white)("XXX")x+5y-10=0#
[2]#color(white)("XXX")x=2y-8#

Substituting (from [2]) #2y-8# or #x# in [1]
[3]#color(white)("XXX")2y-8+5y-10=0#

[4]#color(white)("XXX")7y-18=0#

[5]#color(white)("XXX")=18/7#

Substituting #18/7# for #y# in [2]
[6]#color(white)("XXX")x=2(18/7)-8#

[7]#color(white)("XXX")x=-20/7#