# How do you solve the system of equations -x - 6y = - 10 and x + 9y = 16?

$\left(- 2 , 2\right)$
the second equation gives $x = 16 - 9 y$, so substituting in the first:
$- 16 + 9 y - 6 y = - 10$, so $3 y = 6 R i g h t a r r o w y = 2$, and putting $y = 2$ in the second equation we get $x = - 2$