How do you solve the system of equations #y=-3x-11# and #y=-2x-8#?

1 Answer
Oct 31, 2016

#x =-3 and y =-2#

Explanation:

Notice that both equations represent the equation of straight lines.

By solving them as a system we are actually finding the point of intersection of the two lines.

You have #color(red)(y) = color(blue)(-2x -8)" and " color(red)(y) = color(blue)(-3x -11)#

#color(white)(xxxxxxxxxxxxxxxxx) color(red)(y = y)#

Which then means #color(blue)(-2x -8)= color(blue)(-3x -11)#

#color(white)(xxxxxxxxxx)-2x +3x = -11+8#

#color(white)(xxxxxxxxxx.xxxxxx)x = -3#

Now find #y#

#y = -2(-3)-8#
#y = +6-8#
#y = -2#

Check:
#y= -3(-3)-11#
#y =+9-11#
#y =-2#