How do you solve the system of equations y=4x+6 and 3x+y=41?

1 Answer

x = 5, y=26

Explanation:

There is 3 ways of doing this problem: Substitution, Elimination or Graphing.
For this problem, substitution would be the easiest way because one equation is already solved.
All you have to do is plug y = 4x + 6 into the 2nd equation.

The whole thing would turn out looking like: 3x+ (4x + 6) = 41

Because 3x and 4x are the same, you would add them together and would get: 7x + 6 = 41

Then bring the 6 over to the other side of the equal sign. Subtract 41 and 6 to get 35.
That would look like: 7x = 35

Finally, divide 35 and 7 to get 5.
35divide 7 = 5
x = 5

Solve for y by substituting in the x value into one of the original equations:

y=4x+6

y=4(5)+6=26

graph{(y-(4x+6))(3x+y-41)=0 [-5, 10, 15, 30]}