How do you solve the system of linear equations x + 3y = 5 and 4x + 5y = 13?

Mar 28, 2018

$y = 1$ $x = 2$

Explanation:

$x + 3 y = 5$
$4 x + 5 y = 13$
try to canceling a variable
$\left(- 4\right) \left(x + 3 y = 5\right)$ = $\left(- 4 x - 12 y = - 20\right)$
$\cancel{- 4 x} - 12 y = - 20$
$\cancel{4 x} + 5 y = 13$
$= - 7 y = - 7$
$y = 1$
plug it into one of the 2 equations
$x + 3 \left(1\right) = 5$
$x = 5 - 3$
$x = 2$