Question

How do you solve the system of linear equations `x + 3y = 5` and `4x + 5y = 13`?

Answer 1

`y=1` `x=2`

Explanation:

`x + 3y = 5`
`4x + 5y = 13`
try to canceling a variable
`(-4)(x +3y = 5)` = `(-4x -12y = -20)`
`cancel(-4x) -12y = -20`
`cancel(4x) + 5y =13`
`= -7y = -7`
`y= 1`
plug it into one of the 2 equations
`x + 3(1) = 5`
`x = 5-3`
`x=2`