# How do you solve the system of linear equations: y = 4x - 3 and y = - 3x - 3?

Nov 14, 2015

I found:
$x = - 3$
$y = 0$

#### Explanation:

You can try substitute the first equation into the second for $y$ so that you get:
$\textcolor{red}{4 x - 3} = - 3 x - 3$ solve for $x$:
$7 x = 0$
$x = \frac{0}{7} = 0$
substitute this into the first equation:
$y = 4 \cdot \textcolor{red}{0} - 3 = - 3$