Question

How do you solve the system s+r=0 and r-s=6?

Answer 1

`r=3`, `s=-3`

Explanation:

Given equations:

`s+r=0\ ...........(1)`

`r-s=6\ ...........(2)`

adding (1) & (2) as follows

`s+r+r-s=0+6`

`2r=6`

`r=6/2=3`

setting `r=3` in (1), we get

`s+3=0`

`s=-3`