Question

How do you solve the system using the substitution method for x+2y=2 and y=2x+6?

Answer 1

I found:
`x=-2`
`y=2`

Explanation:

Take the value of `x` from the first equation:
`x=2-2y` `color(red)((1))`,
and substitute for `x` into the second:
`y=2(2-2y)+6` solve for `y`;
`y=4-4y+6`
`y=10/5=2`
Substitute back into `color(red)((1))` and find `x`:
`x=2-4=-2`