# How do you solve the system x = 2y + 6 and 3x = -2y + 10?

Jun 4, 2016

x=4 and y=-1

#### Explanation:

you would do this by solving by addition/elimination.

$x = 2 y + 6$ plus
$3 x = - 2 y + 10$

add all terms going in a downward direction. $x + 3 x = 4 x$, $2 y - 2 y = 0$ and $6 + 10 = 16$, leaving

$4 x = 16$

$\therefore x = 4$

sub the x value in and test for y.

$4 = 2 y + 6$

$- 2 = 2 y$

$y = 1$

.

$3 \left(4\right) = - 2 y + 10$

$12 = - 2 y + 10$

$2 = - 2 y$

$y = 1$