# How do you solve the system x/3 + 3y/4 = -3 and x/3 - y/4 = 5?

Jun 29, 2016

$x = 9$ and $y = - 8$

#### Explanation:

The equations are:

$\frac{x}{3} + \frac{3 y}{4} = - 3$ ...................(A)

$\frac{x}{3} - \frac{y}{4} = 5$ ...................(B)

Now subtracting (B) from (A)

$\frac{3 y}{4} + \frac{y}{4} = - 3 - 5 = - 8$ or $y = - 8$

Putting this in (B)

$\frac{x}{3} - \frac{- 8}{4} = 5$ or $\frac{x}{3} + 2 = 5$ or $\frac{x}{3} = 3$ or $x = 9$