How do you solve the system #x + y = 5# and #y = 3#?

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Answer 1 · 2018-05-18T12:27:58

See a solution process below:

Substitute #3# (from #y= 3#) for #y# in the first equation and solve for #x#:

#x + y = 5# becomes:

#x + 3 = 5#

#x + 3 - color(red)(3) = 5 - color(red)(3)#

#x + 0 = 2#

#x = 2#

The Solution Is:

#x = 2# and #y = 3#

Or

#(2, 3)#