# How do you solve the system y = 3x - 4 and 2x - y = 1?

May 24, 2015

If you substitute the expression for $y$ given by the first of these equations into the second you find:

$1 = 2 x - y = 2 x - \left(3 x - 4\right) = - x + 4$

Add $x - 1$ to both ends to get:

$x = 3$

Then substitute this value for $x$ into the first equation to get:

$y = 3 x - 4 = \left(3 \times 3\right) - 4 = 9 - 4 = 5$