How do you solve the systems of equations #2x+3y=10# and #3x-10y=15#?

Question

9150 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-03T07:17:10

Just arrange the equations. #x=5# and #y=0#

#2x+3y = 10#
or
#-6x -9y = -30# (after multiplying -3 (all terms)).

#3x-10y =15#
or
#6x - 20y = 30# (after multiplying 2 (all terms)).

Add them:
#-6x - 10 y = -30#
#6x - 20y = 30#

#-30y = 0#
#y=0#

Use the first equation to find x:
#2x + 3y = 10#

#2x=10# (because y is zero)

#x=10/2 = 5#