# How do you solve the systems of equations 2x+3y=10 and 3x-10y=15?

Jul 3, 2018

#### Answer:

Just arrange the equations. $x = 5$ and $y = 0$

#### Explanation:

$2 x + 3 y = 10$
or
$- 6 x - 9 y = - 30$ (after multiplying -3 (all terms)).

$3 x - 10 y = 15$
or
$6 x - 20 y = 30$ (after multiplying 2 (all terms)).

Add them:
$- 6 x - 10 y = - 30$
$6 x - 20 y = 30$

$- 30 y = 0$
$y = 0$

Use the first equation to find x:
$2 x + 3 y = 10$

$2 x = 10$ (because y is zero)

$x = \frac{10}{2} = 5$