How do you solve the triangle given ∠C = 68°, ∠B = 24°, b = 11?

1 Answer
Mar 28, 2017

/_A=88°, a= 27,c=25

Explanation:

First draw a triangle then find /_A. The diagram will enable you to know exactly what you are ealing with.

/_A+/_B+/_C=180°

/_A=180°-/_B-/_C

/_A= 180°-24°-68°

/_A=88°

Now that we have /_A, we can use the law of sine to find a which is the length opposite /_A.

(sinA)/a=(sinB)/b

a*sinB=b*sinA

(a*cancel(sinB))/cancelsinB=(b*sinA)/sinB

a=(11*sin88°)/(sin24°)

a=27

Now use the sine rule again to colve for c

(sin C)/c=(sinB)/b

c=(b*sinC)/sinB

c=(11*sin68°)/sin24°

c=25