Question

How do you solve the triangle of `A=76^circ, a=34, b=21`?

Answer 1

See the following :)

Explanation:

By the Law of Sines, `(sinA)/a = (sinB)/b = (sinC)/c`
For this question, we know that `A= 76^@, a= 34 and b=21`, and we can simply plug in the numbers and get B:

`[sin(76^@)]/34 = (sin B)/21`

`B= 36.81980185^@`

`A+B+C=180^@` (angle sum of triangle)
`C=67.18019815^@`

`[sin(76^@)]/34 = (sin C)/c`
`[sin(76^@)]/34 = (sin67.18019815^@ )/c`
`c=32.29818587`

Hope this can help you :)