Question

How do you solve the triangle when b= 2.8 A=53 degrees B= 61 degrees?

Answer 1

See below

Explanation:

We have `hatA=53º`, `hatB=61º` and `b=2.8`

The other angle `hatC=180-(61+53)=66º`

The other two sides `a` and `c` we can obtain thru sin's theorem

`a/sinA=b/sinB=c/sinC`

`a/(sin53º)=2.8/(sin61º)`, Then `a=2.8·sin53/sin61`

`c/(sin66º)=2.8/(sin61º)`, Then `c=2.8·sin66/sin61`