How do you solve this equation: cos(4x- Pi/4)= √2/2 ?

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Answer 1 · 2018-05-21T01:17:49

#x= 0+pi/2n, pi/8+pi/2n#

#cos(4x- pi/4)= sqrt2/2#

Let #u# be #(4x- pi/4)#

#cosu= sqrt2/2#

#u=-pi/4, pi/4#

#4x-pi/4= -pi/4, pi/4#

#4x= 0+2pin, pi/2+2pin#

#x= 0+pi/2n, pi/8+pi/2n#

Where #n# is an element of all integers