How do you solve this system of equations: #5x - 3y = 58 and 7x + 3y = 38#?

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Answer 1 · 2017-10-06T18:02:53

See explanation.

The coefficients of #y# in both equations are opposite numbers, so if you add the equations you get equation with one variable only #x#:

#{(5x-3y=58),(7x+3y=38):}#

#12x=96#

#x=8#

Now we have to substitute #x# in any of the equations:

#5*8-3y=58#

#40-3y=58#

#-3y=18#

#y=-6#

The solution of the system is: #{(x=8),(y=-6):}#