How do you solve this system of equations using substitution?

Question

#y=-8x#
#2x+4y=0#

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Answer 1 · 2017-03-14T05:50:41

# x=0, y=0.#

#because, y=-8x,# we substitute #-8x for y# in #2x+4y=0# & get,

#2x+4(-8x)=0 rArr 2x-32x=0 rArr -30x=0 rArr x=0/-30=0.#

Accordingly, #y=-8x=-8(0)=0.#

Thus, #x=0, y=0# is a Soln.

Also, these roots satisfy the given eqns.

Hence, the soln. # x=0, y=0.#

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