# How do you solve this system of equations: y= 2x - 7 , 3x + y = 8?

Jun 25, 2018

$\left(3 , - 1\right)$

#### Explanation:

We already have $y$ solved for in terms of $x$, so we can plug this value into the second equation. This gives us

$3 x + \textcolor{s t e e l b l u e}{2 x - 7} = 8$

Note that what I have in blue is $y$. This simplifies to

$5 x - 7 = 8$

Adding $7$ to both sides gives us

$5 x = 15$

Dividing both sides by $5$, we get

$\textcolor{b l u e}{x = 3}$

To solve for $y$, we can plug this value of $x$ into the first equation

$y = 2 x - 7$

$y = 2 \left(3\right) - 7 = 6 - 7 = \textcolor{s t e e l b l u e}{- 1}$

The solution of these two equations is at the point

$\left(3 , - 1\right)$

Hope this helps!