How do you solve this system of equations: #y= 5- x and 4x - 2y = 2#?

1 Answer
Jim G.
Nov 30, 2017

#(x,y)to(2,3)#

Explanation:

#y=5-xto(1)#

#4x-2y=2to(2)#

#color(blue)"substitute "(1)" into "(2)#

#4x-2(5-x)=2#

#rArr4x-10+2x=2#

#rArr6x-10=2#

#"add 10 to both sides"#

#rArr6x=12rArrx=2#

#"substitute this value into equation "(1)#

#rArry=5-2=3#

#"the point of intersection "=(2,3)# graph{(y-5+x)(y-2x+1)=0 [-10, 10, -5, 5]}

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