How do you solve #|u + 1| > 5#?

1 Answer
Narad T.
May 10, 2018

The solution is #u in (-oo, -6) uu(4, +oo)#

Explanation:

This is an inequality with absolute values

#|u+1|>5#

#{(u+1>5),(-u-1>5):}#

#>=>#, #{(u>4),(u<-6):}#

The solution is #u in (-oo, -6) uu(4, +oo)#

graph{|x+1|-5 [-10, 10, -5, 5]}

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