How do you solve #(u ^ { 2} - 6u - 7) ( 2u - 10) = 0#?

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Answer 1 · 2017-08-07T01:49:56

See a solution process below:

First, factor the term on the left as:

#(u - 7)(u + 1)(2u - 10) = 0#

Now, solve each term on the left for #0#

Solution 1

#u - 7 = 0#

#u - 7 + color(red)(7) = 0 + color(red)(7)#

#u - 0 = 7#

#u = 7#

Solution 2

#u + 1 = 0#

#u + 1 - color(red)(1) = 0 - color(red)(1)#

#u + 0 = -1#

#u = -1#

Solution 3

#2u - 10 = 0#

#2u - 10 + color(red)(10) = 0 + color(red)(10)#

#2u - 0 = 10#

#2u = 10#

#(2u)/color(red)(2) = 10/color(red)(2)#

#(color(red)(cancel(color(black)(2)))u)/cancel(color(red)(2)) = 5#

#u = 5#

The Solutions Are: #u = 7# and #u = -1# and #u = 5#