How do you solve using elimination of #-2x=6y+18# and #-29=5y-3x#?

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Answer 1 · 2018-07-11T20:29:52

#x=3,y=-4#

Dividing the first equation by #-2' we get

#x=-3y-9#
substituting this )for #y# in the second equation we get

#5y-3(-3y-9)=-29#

expanding we get

#5y+9y+27=29#

combining like Terms and adding #-27#

so we get

#14y=-56#

so we get

#y=-4#