# How do you solve using elimination of x-y=-3 and 5x+3y=1?

Mar 28, 2018

$\textcolor{b l u e}{x = - 1}$

$\textcolor{b l u e}{y = 2}$

#### Explanation:

$x - y = - 3 \setminus \setminus \setminus \setminus \setminus \left[1\right]$

$5 x + 3 y = 1 \setminus \setminus \setminus \setminus \setminus \setminus \setminus \setminus \left[2\right]$

Multiply $\left[1\right]$ by 5:

$5 x - 5 y = - 15 \setminus \setminus \setminus \setminus \setminus \left[3\right]$

Subtract $\left[2\right]$ from $\left[3\right]$:

$5 x - 5 y = - 15$

$5 x + 3 y = 1$

$0 - 8 y = - 16$

Divide by $- 8$

$y = \frac{- 16}{-} 8 = 2$

Substitute this is $\left[1\right]$

$x - \left(2\right) = - 3$

$x = - 1$
$\textcolor{b l u e}{x = - 1}$
$\textcolor{b l u e}{y = 2}$