How do you solve using the completing the square method # 0=x^2-3x-6#?
We need to add a number to create the constant
Since b = - 3 then
But we already have - 6 = - 24/4 so we need to add 33/4
And we also need to subtract 33/4 to keep the equation true
This results in
Taking the root and adding 3/2 to both sides
gives the result