Question

How do you solve using the completing the square method `2x^2 - 3x +1 = 0`?

Answer 1

Please following my working.

Explanation:

`2x^2 - 3x + 1 = 0`
`x^2 - (3x)/2 + 1/2 = 0`
`x^2 - (3x)/2 + (3/4)^2 = (3/4)^2 - 1/2`
`(x-3/4)^2 = 9/16 - 8/16`
`(x- 3/4)^2 = 1/16`
`x-3/4 = +-1/4`
`x = 3/4+-1/4`

Therefore:
`x = 1, 1/2`