Question

How do you solve using the completing the square method `3x^2 +18x +20 = 0`?

Answer 1

Dividing both sides of the Eq by 3 we have
`x^2+6x+20/3=0`
`=>x^2+2xx3xxx+3^3-3^2+20/3=0`
`=>(x+3)^2-9+20/3=0`
`=>(x+3)^2-7/3=0`
`=>(x+3)^2-(sqrt(7/3))^2=0`
`=>(x+3+sqrt(7/3))(x+3-sqrt(7/3))=0`
`:.`
`(x=-3-sqrt(7/3))`
and
`(x=-3+sqrt(7/3))`