# How do you solve using the completing the square method 4x^2 + 20x + 25 = 49?

Solution x=1; x= -6
$4 {x}^{2} + 20 x + 25 = 49 \mathmr{and} {\left(2 x + 5\right)}^{2} = {7}^{2} \mathmr{and} 2 x + 5 = \pm 7 \therefore e i t h e r 2 x = 7 - 5 = 2 \therefore x = 1 \mathmr{and} 2 x = - 7 - 5 \therefore x = - 6 \therefore$Solution x=1; x= -6[Ans]