# How do you solve using the completing the square method 5x^2-15x=-2?

$x = 2.86 \left(2 \mathrm{dp}\right) \mathmr{and} x = 0.14 \left(2 \mathrm{dp}\right)$
$5 {x}^{2} - 15 x = - 2 \mathmr{and} 5 {x}^{2} - 15 x = - 2 \mathmr{and} 5 \left({x}^{2} - 3 x\right) = - 2 \mathmr{and} {x}^{2} - 3 x = - \frac{2}{5} \mathmr{and} {x}^{2} - 3 x + {\left(\frac{3}{2}\right)}^{2} = - \frac{2}{5} + \frac{9}{4} \mathmr{and} {\left(x - \frac{3}{2}\right)}^{2} = \frac{37}{20} \mathmr{and} x - \frac{3}{2} = \pm \sqrt{\frac{37}{20}} \mathmr{and} x = \frac{3}{2} \pm \sqrt{\frac{37}{20}} \therefore x = 2.86 \left(2 \mathrm{dp}\right) \mathmr{and} x = 0.14 \left(2 \mathrm{dp}\right)$ [Ans]