Question

How do you solve using the completing the square method `x^2+1.4x=1.2`?

Answer 1

The constant is already on the right hand side. Add a missing term to each side to create the square of a binomial on the left.
`x = 0.6, x = -2`

Explanation:

[add `(b/2)^2` to both sides]

#x2 + 1.4x + (1.4/2)^2 = 1.2 + (1.4/2)^2

`(x + 0.7)^2 = 1.69` `" sqrt both sides"`

`x + 0.7 = +-1.3`

`x = +1.3 - 0.7 or x= -1.3 -0.7`

`x = 0.6, x = -2`