How do you solve using the completing the square method #x^2 - 2x = 0#?

1 Answer
Apr 3, 2017

Answer:

#x=0" or " x=2#

Explanation:

To #color(blue)"complete the square "#on the left side of the equation.

#• " add " (1/2 "coefficient of the x term")^2# to both sides.

#"That is " ((-2)/2)^2=1#

#rArrx^2-2xcolor(red)(+1)=0color(red)(+1)#

#rArr(x-1)^2=1#

#"Take " color(blue)"the square root of both sides"#

#sqrt((x-1)^2)=+-sqrt1#

#rArrx-1=+-1#

#rArrx=+1+1=2larrcolor(red)"first solution" " or"#

#x=-1+1=0larrcolor(red)" second solution"#