How do you solve using the completing the square method #x^2 - 2x = 0#?
1 Answer
Apr 3, 2017
Explanation:
To
#color(blue)"complete the square "# on the left side of the equation.
#• " add " (1/2 "coefficient of the x term")^2# to both sides.
#"That is " ((-2)/2)^2=1#
#rArrx^2-2xcolor(red)(+1)=0color(red)(+1)#
#rArr(x-1)^2=1#
#"Take " color(blue)"the square root of both sides"#
#sqrt((x-1)^2)=+-sqrt1#
#rArrx-1=+-1#
#rArrx=+1+1=2larrcolor(red)"first solution" " or"#
#x=-1+1=0larrcolor(red)" second solution"#