# How do you solve using the completing the square method x^2-3/2x-23/16=0?

Mar 14, 2016

$x = \frac{3}{4} \pm \frac{\sqrt{59}}{4}$

#### Explanation:

${x}^{2} - \frac{3 x}{2} - \frac{23}{26}$.
${x}^{2} - \frac{3 x}{2} = \frac{12}{16}$
${x}^{2} - \frac{3 x}{2} + \frac{9}{4} = \frac{12}{16} + \frac{9}{4}$
${\left(x - \frac{3}{4}\right)}^{2} = \frac{59}{16}$
$\left(x - \frac{3}{4}\right) = \pm \frac{\sqrt{59}}{4}$
$x = \frac{3}{4} \pm \frac{\sqrt{59}}{4}$