Question

How do you solve using the completing the square method `x^2-3/2x-23/16=0`?

Answer 1

`x = 3/4 +- sqrt59/4`

Explanation:

`x^2 - (3x)/2 - 23/26`.
`x^2 - (3x)/2 = 12/16`
`x^2 - (3x)/2 + 9/4 = 12/16 + 9/4`
`(x - 3/4)^2 = 59/16`
`(x - 3/4) = +- sqrt59/4`
`x = 3/4 +- sqrt59/4`