# How do you solve using the completing the square method x^2 + 3x - (7/4) = 0?

May 7, 2016

${x}^{2}$ + 3x -$\left(\frac{7}{4}\right)$ = 0
${\left(x + \left(\frac{3}{2}\right)\right)}^{2}$ - ${\left(\frac{3}{2}\right)}^{2}$ - $\left(\frac{7}{4}\right)$ =0
${\left(x + \frac{3}{2}\right)}^{2}$ - 4 =0
Hence the vertex has a coordinate of y= -4 and x = - $\frac{3}{2}$
Maximum point = ($- \frac{3}{2}$, -4)