How do you solve using the completing the square method #x^2-4x+1=0#?
1 Answer
Mar 20, 2016
See explanation...
Explanation:
In addition to completing the square, I will use the difference of squares identity, which can be written:
#a^2-b^2 = (a-b)(a+b)#
with
#0 = x^2-4x+1#
#= x^2-4x+4-3#
#=(x-2)^2-(sqrt(3))^2#
#=((x-2)-sqrt(3))((x-2)+sqrt(3))#
#=(x-2-sqrt(3))(x-2+sqrt(3))#
So:
