# How do you solve using the completing the square method x^2+4x=5?

##### 1 Answer
Aug 4, 2016

$x = 1$
$x = - 5$

#### Explanation:

${x}^{2} + 4 x = 5$
or
${x}^{2} + 4 x + 4 = 5 + 4$
or
${x}^{2} + 2 \left(x\right) \left(2\right) + {2}^{2} = 9$
or
${\left(x + 2\right)}^{2} = {3}^{2}$
or
$x + 2 = \pm 3$
or
$x = - 2 \pm 3$
or
$x = - 2 + 3$
or
$x = 1$---------------Ans $1$
or
$x = - 2 - 3$
or
$x = - 5$--------------Ans $2$