How do you solve using the completing the square method #x^2 - 6x + 10 = 0#?

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Answer 1 · 2017-01-31T04:48:43

#x=3+-i#

#x^2-6x+10=0#

consider #coefficient of x, divide by 2

#(x-6/2)^2 -(-6/2)^2+10=0#

#(x-3)^2-9+10=0#

#(x-3)^2+1=0#

#(x-3)^2=-1#

#i^2=-1#, then #i=+-sqrt(-1)#

#x-3 = +-sqrt(-1)=+-i#

#x=3+-i#