# How do you solve using the completing the square method x^2-6x=27 ?

Jul 30, 2016

$x = 9$
$x = - 3$

#### Explanation:

${x}^{2} - 6 x = 27$
or
${x}^{2} - 6 x + 9 = 27 + 9$
or
${x}^{2} - 2 x \left(3\right) + {3}^{2} = 36$
or
${\left(x - 3\right)}^{2} = {6}^{2}$
or
$x - 3 = \pm 6$
or
$x = 3 + 6 = 9$
or
$x = 3 - 6 = - 3$