# How do you solve using the completing the square method x^2-6x-9=0?

$x = 3 \pm 3 \sqrt{2}$
${\left(x - 3\right)}^{2} - 18 = 0$
$\left(x - 3\right) = \pm \sqrt{18} = \pm 3 \sqrt{2}$
$x = 3 \pm 3 \sqrt{2}$