How do you solve using the completing the square method x^2-8x+15=0?

${x}^{2} - 8 x = - 15 \to {x}^{2} - 8 x + {\left(- 4\right)}^{2} = - 15 + 16 \to {\left(x - 4\right)}^{2} = 1 \to x - 4 = \pm 1 \to x = 5 \mathmr{and} x = 3$