# How do you solve using the completing the square method x^2 - 8x + 20 = 5?

Solution: $x = 5 \mathmr{and} x = 3$
${x}^{2} - 8 x + 20 = 5 \mathmr{and} {x}^{2} - 8 x + 16 + 4 = 5 \mathmr{and} {x}^{2} - 8 x + 16 = 5 - 4 \mathmr{and} {\left(x - 4\right)}^{2} = 1 \mathmr{and} x - 4 = \pm \sqrt{1} \mathmr{and} x - 4 = \pm 1 \therefore x = 4 + 1 = 5 \mathmr{and} x = 4 - 1 = 3$
Solution: $x = 5 \mathmr{and} x = 3$ [Ans]