Question

How do you solve using the completing the square method `x^2 - 8x -48 = 0`?

Answer 1

as follows

Explanation:

`x^2-8x-48=0`
`=>x^2-2*x*4+4^2-16-48=0`
`=>x^2-2*x*4+4^2=64`
`=>(x-4)^2=64`
`=>(x-4)=+-sqrt64=+-8`
`:.x =8+4=12` and `x =-8+4=-4`