# How do you solve using the completing the square method y^2 + 16y = 2?

May 25, 2016

$y = - 8 \pm \sqrt{66}$

#### Explanation:

find the number needed to complete the square:
${\left(\frac{b}{2}\right)}^{2} = {\left(\frac{16}{2}\right)}^{2} = 64$
add to both sides of w=equation
${y}^{2} + 16 y + 64 = 2 + 64$
factor and simplify
$\left(y + 8\right) \left(y + 8\right) = 66 \to {\left(y + 8\right)}^{2} = 66$
take square root of both sides
$y + 8 = \pm \sqrt{66}$
subtract 8 from both sides
$y = - 8 \pm \sqrt{66}$