Question

How do you solve using the quadratic formula `2x^2 – 4x + 7 = 0`?

Answer 1

D = d^2 = b^3 - 4ac = 16 - 56 = -40 -> `d = 2i.(sqr10)`

Since D < 0, there are no real roots. There are 2 complex roots:

`x1 = -b/(2a) + d/(2a) = 1 + (sqr10.i)/2`

`x2 = 1 - (sqr10.i)/2`