# How do you solve using the quadratic formula 2x^2 – 4x + 7 = 0?

D = d^2 = b^3 - 4ac = 16 - 56 = -40 -> $d = 2 i . \left(s q r 10\right)$
$x 1 = - \frac{b}{2 a} + \frac{d}{2 a} = 1 + \frac{s q r 10. i}{2}$
$x 2 = 1 - \frac{s q r 10. i}{2}$