Question

How do you solve using the quadratic formula `3x(x - 2) = 1`?

Answer 1

f(x) = 3x^2 - 6x - 1 = 0

#D = d^2 = b^2 - 4ac = 36 + 12 = 48 = 16.3 -> d = +-4.sqr3#

`x = 6/6 + (4.sqr3)/6`= `1 + (sqr3)/3`

`x = 6/6 - (sqr3)/3 = 1 - (sqr3)/3`