Question

How do you solve using the quadratic formula `4x-3x^2=1`?

Answer 1

The quadratic formula for roots
`x=(-b+-sqrt(b^2-4ac))/(2a)`
is applicable to equations in the form:
`ax^2+bx+c=0`

So first it will be necessary to rearrange `4x-3x^2=1` as
`3x^2-4x+1=0`

Then
`x= (4+-sqrt(4^2-4(3)(1)))/(2(3))`

`= (4+-2)/6`

`x=1` or `x=1/3`