How do you solve using the quadratic formula #6x^2 + 12x=-3#?

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Answer 1 · 2015-05-12T15:37:46

A quadratic equation is written in the form:
#ax^2 + bx + c = 0#

The given equation #6x^2 + 12x = -3# can be rewritten as #6x^2+12x+3=0#

Where:
#a=6#
#b=12#
#c=3#

The quadratic formula can be used to find the roots of any quadratic equation.

#x= (-b+- sqrt(b^2-4ac))/(2a)#

So I encourage you to plug in the values from this equation and simplify.

The answers should be #x = −1.70711 and x= −0.292893#